BODMAS Rule Questions

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BODMAS rule questions with solutions are provided here for students to practice and understand the precedence of arithmetic operations. BODMAS is an acronym for brackets, order/of, division, multiplication, addition and subtraction. It tells us the order of operations needed to be followed while solving any expression with more than one arithmetic operation.

Sometimes this BODMAS rule is also referred to as the PEMDAS rule (Parenthesis, Exponent, Multiplication, Division, Addition and Subtraction) or BIDMAS rule (Brackets, Index, Division, Multiplication, Addition and Subtraction).

BODMAS Rule

Learn about the tips to remember BODMAS Rule.

Video Lesson on BODMAS Rule

BODMAS Rule Questions with Solutions

Now that we have learnt about the BODMAS rule for the order of arithmetic operations, let us solve a few questions to practice the concept.

Question 1:

Evaluate: 2 + 4 ÷ (22 + 6) × 2.

Solution:

First, we solve the parentheses, and we get

Now, perform the division 4/28

Now, we do the multiplication 1/7 × 2

Question 2:

Solution:

Question 3:

Evaluate: 5 × (2 × 3 4 ) ÷ 6 + 7 – 8

Solution:

5 × (2 × 3 4 ) ÷ 6 + 7 – 8

= 5 × (2 × 81) ÷ 6 + 7 – 8

= 5 × 162 ÷ 6 + 7 – 8

Question 4:

Evaluate: 2 of 5 ÷ 5 + 3

Solution:

2 of 5 ÷ 5 + 3 = (2 × 5) ÷ 5 + 3

Types of Brackets:

Sometimes we need to use more than one type of bracket. The brackets which are used are –

We should start solving from the innermost bracket. Generally, vinculum is used as innermost bracket, then parentheses, then braces, then square brackets.

Question 5:

\(\begin[\left\<\left ( 125 \times \overline<33 \div 11>+ 2 \right ) \times 34\right\>\div 493]\times \frac\end \)

Solution:

We start by solving the innermost bar bracket

\(\begin[\left\<\left ( 125 \times \overline<33 \div 11>+ 2 \right ) \times 34\right\>\div 493]\times \frac\end \)

Also Read:

Question 6:

\(\begin\frac\times \frac\div \frac+\frac\end \)

Solution:

\(\begin\frac\times \frac\div \frac+\frac\end \) \(\begin=\frac\times \frac+\frac= \frac+\frac= \frac\end \)

Question 7:

Evaluate: [(18 – 6) ÷ 4] + [72 – 12 ÷ 3 of 2]

Solution:

[(18 – 6) ÷ 4] + [72 – 12 ÷ 3 of 2] = [(18 – 6) ÷ 4] + [72 – 12 ÷ (3 × 2)]

= [12 ÷ 4] + [72 – 12 ÷ 6]

= 3 + [72 – 2] = 3 + 70 = 73.

Question 8:

Evaluate: [15% of 150] + 23 ÷ 115

Solution:

[15/100 × 150] + 23 ÷ 115

Question 9:

Simplify: 12 + 6 × 27 ÷ 3 + 2 – 16 ÷ 8 × 2

Solution:

12 + 6 × 27 ÷ 3 + 2 – 16 ÷ 8 × 2

= 12 + 6 × 9 + 2 – 2 × 2

Question 10:

Evaluate: 0.07 × 0.28 ÷ 0.02 + 0.48 – 2.48 ÷ 0.04

Solution:

0.07 × 0.28 ÷ 0.02 + 0.48 – 2.48 ÷ 0.04

= 0.07 × 14 + 0.48 – 62